What is the slope of (19/2 ,-5/3),(-3/2 ,-7/24) ?

The slope of (19/2 ,-5/3),(-3/2 ,-7/24) is m=-1/8

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slope of (19/2 ,-5/3),(-3/2 ,-7/24)

slope

(\frac{19}{2}, - \frac{5}{3}), (- \frac{3}{2}, - \frac{7}{24})

m = - \frac{1}{8}

Solution steps

Slope between two points: Slope

= \frac{y _{2} - y _{1}}{x _{2} - x _{1}}

(x_{1}, y_{1}) = (\frac{19}{2}, - \frac{5}{3}), (x_{2}, y_{2}) = (- \frac{3}{2}, - \frac{7}{24})

m = \frac{- \frac{7}{24} - ( - \frac{5}{3} )}{- \frac{3}{2} - \frac{19}{2}}

Refine

m = - \frac{1}{8}

\int \frac{sec ( x ) tan ( x )}{sec ( x ) - 4} d x

y^{^{''}} + 4 y^{^{'}} + 4 y = 0, y (0) = 2, y^{^{'}} (0) = 4

\int \frac{1}{( 1 - t ) ^{2}} d t

\frac{d}{d x} (3 sin (6 x))

\int \frac{1}{2} x^{3} 4 - x^{2} d x

What is the slope of (19/2 ,-5/3),(-3/2 ,-7/24) ?
The slope of (19/2 ,-5/3),(-3/2 ,-7/24) is m=-1/8