What is the derivative of 3sin(6x) ?

The derivative of 3sin(6x) is 18cos(6x)

What is the first derivative of 3sin(6x) ?

The first derivative of 3sin(6x) is 18cos(6x)

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\frac{d}{d x} (3 sin (6 x))

18 cos (6 x)

Solution steps

\frac{d}{d x} (3 sin (6 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (sin (6 x))

Apply the chain rule:

cos (6 x) \frac{d}{d x} (6 x)

= cos (6 x) \frac{d}{d x} (6 x)

\frac{d}{d x} (6 x) = 6

= 3 cos (6 x) \cdot 6

Simplify

= 18 cos (6 x)

\int \frac{1}{2} x^{3} 4 - x^{2} d x

y = \frac{1}{x ^{8}}

\int_{0}^{3} x e^{x} d x

\int_{0}^{6} (6 - x)^{2} d x

\int_{2}^{4} x d x

What is the derivative of 3sin(6x) ?
The derivative of 3sin(6x) is 18cos(6x)
What is the first derivative of 3sin(6x) ?
The first derivative of 3sin(6x) is 18cos(6x)