What is the derivative of y= 1/(x^8) ?

The derivative of y= 1/(x^8) is -8/(x^9)

What is the first derivative of y= 1/(x^8) ?

The first derivative of y= 1/(x^8) is -8/(x^9)

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derivative of

y = \frac{1}{x ^{8}}

- \frac{8}{x ^{9}}

Solution steps

\frac{d}{d x} (\frac{1}{x ^{8}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} (x^{- 8})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 8 x^{- 8 - 1}

Simplify

- 8 x^{- 8 - 1} : - \frac{8}{x ^{9}}

= - \frac{8}{x ^{9}}

\int_{0}^{3} x e^{x} d x

\int_{0}^{6} (6 - x)^{2} d x

\int_{2}^{4} x d x

2 x^{2}, 2 x + 6, 1, 2

sin (2 x) d x + cos (7 y) d y = 0

What is the derivative of y= 1/(x^8) ?
The derivative of y= 1/(x^8) is -8/(x^9)
What is the first derivative of y= 1/(x^8) ?
The first derivative of y= 1/(x^8) is -8/(x^9)