What is the solution for (dy)/(dx)= 1/x (y^2+1y) ?

The solution for (dy)/(dx)= 1/x (y^2+1y) is y=(e^{c_{1}}x)/(1-e^{c_{1)}x}

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(dy)/(dx)= 1/x (y^2+1y)

\frac{d y}{d x} = \frac{1}{x} (y^{2} + 1 y)

y = \frac{e ^{c_{1}} x}{1 - e ^{c_{1}} x}

Solution steps

\frac{d y}{d x} = \frac{1}{x} (y^{2} + 1 y)

Solve separable ODE:

y = \frac{e ^{c_{1}} x}{1 - e ^{c_{1}} x}

y = \frac{e ^{c_{1}} x}{1 - e ^{c_{1}} x}

\frac{d}{d x} ((x + 1)^{\frac{1}{x}})

\int sin (x) cos (x) d x

\int_{0}^{5} \frac{1}{x ^{\frac{14}{13}}} d x

f (x) = 3 x^{5} e^{2 x}

\frac{d}{d x} (9 x + 8)

What is the solution for (dy)/(dx)= 1/x (y^2+1y) ?
The solution for (dy)/(dx)= 1/x (y^2+1y) is y=(e^{c_{1}}x)/(1-e^{c_{1)}x}