What is the solution for (dy}{dx}=\frac{(x-1))/y ?

The solution for (dy}{dx}=\frac{(x-1))/y is y=sqrt(x^2-2x+c_{1)},y=-sqrt(x^2-2x+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy}{dx}=\frac{(x-1))/y

\frac{d y}{d x} = \frac{( x - 1 )}{y}

y = x^{2} - 2 x + c_{1}, y = - x^{2} - 2 x + c_{1}

Solution steps

\frac{d y}{d x} = \frac{( x - 1 )}{y}

Solve separable ODE:

y = x^{2} - 2 x + c_{1}, y = - x^{2} - 2 x + c_{1}

y = x^{2} - 2 x + c_{1}, y = - x^{2} - 2 x + c_{1}

f (x) = x^{0.5}

y^{^{'}} + \frac{4}{x} y = x^{4}

\int x ln (x) d x

\int \frac{1}{5 + 3 cos ( 2 x )} d x

\int 7 x^{3} e^{- x^{2}} d x

What is the solution for (dy}{dx}=\frac{(x-1))/y ?
The solution for (dy}{dx}=\frac{(x-1))/y is y=sqrt(x^2-2x+c_{1)},y=-sqrt(x^2-2x+c_{1)}