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Popular >

y^'e^{-x}=y^2+9

Solution

y^{^{'}} e^{- x} = y^{2} + 9

Solution

y = 3 tan (3 e^{x} + c_{1})

Solution steps

y^{'} (x) e^{- x} = y^{2} + 9

Solve separable ODE:

y = 3 tan (3 e^{x} + c_{1})

y = 3 tan (3 e^{x} + c_{1})

Graph

Popular Examples

(d^2)/(dx^2)(2cos(x/2))

\frac{d ^{2}}{d x ^{2}} (2 cos (\frac{x}{2}))

derivative of 2e^{x^2-5x}derivative of

2 e^{x^{2} - 5 x}

limit as x approaches-3 of (x^2+9)/(x+3)

x \to - 3 lim (\frac{x ^{2} + 9}{x + 3})

derivative of-1/2 x^{-3/2}

\frac{d}{d x} (- \frac{1}{2} x^{- \frac{3}{2}})

y^{''}-2y^'+5y=e^xsin(2x)

y^{^{''}} - 2 y^{^{'}} + 5 y = e^{x} sin (2 x)

Frequently Asked Questions (FAQ)

What is the solution for y^'e^{-x}=y^2+9 ?
The solution for y^'e^{-x}=y^2+9 is y=3tan(3e^x+c_{1})