What is area sqrt(1+3x),3<= x<= 9 ?

The answer to area sqrt(1+3x),3<= x<= 9 is (112sqrt(7)-20sqrt(10))/9

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area sqrt(1+3x),3<= x<= 9

area

1 + 3 x, 3 \leq x \leq 9

\frac{112 7 - 20 10}{9}

Decimal

25.89762 \dots

Solution steps

Apply the area formula:

\int_{3}^{9} 1 + 3 x d x

Solve

\int_{3}^{9} 1 + 3 x d x : \frac{112 7 - 20 10}{9}

The area is:

= \frac{112 7 - 20 10}{9}

\frac{d}{d x} (- 27 cos (3 x))

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\frac{d}{d x} (2 \cdot c \cdot x - x^{2})

\frac{d}{d x} (e^{- x} sin (y))

What is area sqrt(1+3x),3<= x<= 9 ?
The answer to area sqrt(1+3x),3<= x<= 9 is (112sqrt(7)-20sqrt(10))/9