What is the derivative of x^4-3x ?

The derivative of x^4-3x is 4x^3-3

What is the first derivative of x^4-3x ?

The first derivative of x^4-3x is 4x^3-3

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derivative of

x^{4} - 3 x

4 x^{3} - 3

Solution steps

\frac{d}{d x} (x^{4} - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (3 x)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (3 x) = 3

= 4 x^{3} - 3

x \to - 0.1 lim (\frac{e ^{x} - 1}{x})

\frac{\partial}{\partial x} (\frac{3}{4 y ^{4} x ^{\frac{1}{4}}})

\frac{d x}{d t} = 7 x t^{4}

\int_{- 1}^{3} (2 x^{2} - 8) d x

\frac{d}{d x} (- \frac{18}{a x})

What is the derivative of x^4-3x ?
The derivative of x^4-3x is 4x^3-3
What is the first derivative of x^4-3x ?
The first derivative of x^4-3x is 4x^3-3