What is the derivative of y=x^2+e^xsqrt(x) ?

The derivative of y=x^2+e^xsqrt(x) is 2x+e^xsqrt(x)+(e^x)/(2sqrt(x))

What is the first derivative of y=x^2+e^xsqrt(x) ?

The first derivative of y=x^2+e^xsqrt(x) is 2x+e^xsqrt(x)+(e^x)/(2sqrt(x))

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derivative of

y = x^{2} + e^{x} x

2 x + e^{x} x + \frac{e ^{x}}{2 x}

Solution steps

\frac{d}{d x} (x^{2} + e^{x} x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (e^{x} x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (e^{x} x) = e^{x} x + \frac{e ^{x}}{2 x}

= 2 x + e^{x} x + \frac{e ^{x}}{2 x}

x \to 0 lim (\frac{1 - cos ( 7 x )}{x})

11 (t + 1) y^{^{'}} - 9 y = 18 t

y^{^{'}} + \frac{1}{t} y = e^{- t^{2}}, y (1) = 12

\frac{d}{d x} (lo g_{2} ((5 x - 1)^{3}))

\frac{d}{d x} (\frac{x}{x + \frac{b}{x}})

What is the derivative of y=x^2+e^xsqrt(x) ?
The derivative of y=x^2+e^xsqrt(x) is 2x+e^xsqrt(x)+(e^x)/(2sqrt(x))
What is the first derivative of y=x^2+e^xsqrt(x) ?
The first derivative of y=x^2+e^xsqrt(x) is 2x+e^xsqrt(x)+(e^x)/(2sqrt(x))