What is the limit as x approaches 4 of sqrt(x^2-16) ?

The limit as x approaches 4 of sqrt(x^2-16) is 0

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limit as x approaches 4 of sqrt(x^2-16)

x \to 4 lim (x^{2} - 16)

0

Solution steps

x \to 4 lim (x^{2} - 16)

Plug in the value

x = 4

= 4^{2} - 16

Simplify

= 0

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What is the limit as x approaches 4 of sqrt(x^2-16) ?
The limit as x approaches 4 of sqrt(x^2-16) is 0