What is (\partial)/(\partial x)(y^2sin(xz)) ?

The answer to (\partial)/(\partial x)(y^2sin(xz)) is y^2cos(xz)z

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(\partial)/(\partial x)(y^2sin(xz))

\frac{\partial}{\partial x} (y^{2} sin (x z))

y^{2} cos (x z) z

Solution steps

\frac{\partial}{\partial x} (y^{2} sin (x z))

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{2} \frac{\partial}{\partial x} (sin (x z))

Apply the chain rule:

cos (x z) \frac{\partial}{\partial x} (x z)

= cos (x z) \frac{\partial}{\partial x} (x z)

\frac{\partial}{\partial x} (x z) = z

= y^{2} cos (x z) z

x \to 4 + lim (\frac{1}{x ^{3} - 64})

\int sec^{6} (2 x) d x

\int \frac{4}{5 + 2 x - x ^{2}} d x

3 (s^{3} - s^{2})

\frac{d}{d x} (e^{8 x s i n (2 x)})

What is (\partial)/(\partial x)(y^2sin(xz)) ?
The answer to (\partial)/(\partial x)(y^2sin(xz)) is y^2cos(xz)z