What is the derivative of e^{8xsin(2x}) ?

The derivative of e^{8xsin(2x}) is e^{8xsin(2x)}*8(sin(2x)+2xcos(2x))

What is the first derivative of e^{8xsin(2x}) ?

The first derivative of e^{8xsin(2x}) is e^{8xsin(2x)}*8(sin(2x)+2xcos(2x))

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\frac{d}{d x} (e^{8 x s i n (2 x)})

e^{8 x s i n (2 x)} \cdot 8 (sin (2 x) + 2 x cos (2 x))

Solution steps

\frac{d}{d x} (e^{8 x s i n (2 x)})

Apply the chain rule:

e^{8 x s i n (2 x)} \frac{d}{d x} (8 x sin (2 x))

= e^{8 x s i n (2 x)} \frac{d}{d x} (8 x sin (2 x))

\frac{d}{d x} (8 x sin (2 x)) = 8 (sin (2 x) + 2 x cos (2 x))

= e^{8 x s i n (2 x)} \cdot 8 (sin (2 x) + 2 x cos (2 x))

\frac{d}{d x} (\frac{2 x}{9 x ^{2} + 1})

\int \frac{1}{4 x ^{2} + 2 x + 1} d x

\frac{1}{u}

\int_{0}^{0.5} tan (x) d x

\int [(x + 3) (x - 4) + \frac{1}{x ^{2}}] d x

What is the derivative of e^{8xsin(2x}) ?
The derivative of e^{8xsin(2x}) is e^{8xsin(2x)}*8(sin(2x)+2xcos(2x))
What is the first derivative of e^{8xsin(2x}) ?
The first derivative of e^{8xsin(2x}) is e^{8xsin(2x)}*8(sin(2x)+2xcos(2x))