What is the derivative of sin(-3x) ?

The derivative of sin(-3x) is -cos(3x)*3

What is the first derivative of sin(-3x) ?

The first derivative of sin(-3x) is -cos(3x)*3

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derivative of

sin (- 3 x)

- cos (3 x) \cdot 3

Solution steps

\frac{d}{d x} (sin (- 3 x))

Simplify

sin (- 3 x) : - sin (3 x)

= \frac{d}{d x} (- sin (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (sin (3 x))

Apply the chain rule:

cos (3 x) \frac{d}{d x} (3 x)

= cos (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= - cos (3 x) \cdot 3

\frac{x ^{3}}{72} + \frac{6}{x}

\frac{d}{d x} ((x - sin (x))^{5})

\frac{d}{d x} ((x^{3} + 3 x^{2} + x - 1) (2 x^{2} - x + 1))

y = \frac{1}{3} - 6

co sin (o)

What is the derivative of sin(-3x) ?
The derivative of sin(-3x) is -cos(3x)*3
What is the first derivative of sin(-3x) ?
The first derivative of sin(-3x) is -cos(3x)*3