What is the derivative of-(3x^2)/(4y^2) ?

The derivative of-(3x^2)/(4y^2) is -(3x)/(2y^2)

What is the first derivative of-(3x^2)/(4y^2) ?

The first derivative of-(3x^2)/(4y^2) is -(3x)/(2y^2)

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derivative of

- \frac{3 x ^{2}}{4 y ^{2}}

- \frac{3 x}{2 y ^{2}}

Solution steps

\frac{d}{d x} (- \frac{3 x ^{2}}{4 y ^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{3}{4 y ^{2}} \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{3}{4 y ^{2}} \cdot 2 x^{2 - 1}

Simplify

- \frac{3}{4 y ^{2}} \cdot 2 x^{2 - 1} : - \frac{3 x}{2 y ^{2}}

= - \frac{3 x}{2 y ^{2}}

2 x^{2} + 15

\frac{d}{d x} (\frac{1}{- 3 + ( 3 x + 1 ) ^{2}})

y = sec (x), (\frac{π}{6}, 2 \frac{3}{3})

\frac{d y}{d x} = 1 + 8 y

tan^{8} (x)

What is the derivative of-(3x^2)/(4y^2) ?
The derivative of-(3x^2)/(4y^2) is -(3x)/(2y^2)
What is the first derivative of-(3x^2)/(4y^2) ?
The first derivative of-(3x^2)/(4y^2) is -(3x)/(2y^2)