What is (\partial}{\partial x}(\frac{y-x)/z) ?

The answer to (\partial}{\partial x}(\frac{y-x)/z) is -1/z

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(\partial}{\partial x}(\frac{y-x)/z)

\frac{\partial}{\partial x} (\frac{y - x}{z})

- \frac{1}{z}

Solution steps

\frac{\partial}{\partial x} (\frac{y - x}{z})

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{z} \frac{\partial}{\partial x} (y - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{z} (\frac{\partial}{\partial x} (y) - \frac{\partial}{\partial x} (x))

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (x) = 1

= \frac{1}{z} (0 - 1)

Simplify

= - \frac{1}{z}

\frac{d}{d x} ((x - 2) (x + 2))

t \frac{d y}{d t} - 3 y = \frac{4 t ^{5}}{t ^{2} + 4}

\int 11 sin^{3} (x co) s^{2} x d x

\int \frac{y ^{2}}{y - 1} d y

f (t) = t^{4}

What is (\partial}{\partial x}(\frac{y-x)/z) ?
The answer to (\partial}{\partial x}(\frac{y-x)/z) is -1/z