What is the derivative of-x^3+20x^2+21x ?

The derivative of-x^3+20x^2+21x is -3x^2+40x+21

What is the first derivative of-x^3+20x^2+21x ?

The first derivative of-x^3+20x^2+21x is -3x^2+40x+21

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\frac{d}{d x} (- x^{3} + 20 x^{2} + 21 x)

- 3 x^{2} + 40 x + 21

Solution steps

\frac{d}{d x} (- x^{3} + 20 x^{2} + 21 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{3}) + \frac{d}{d x} (20 x^{2}) + \frac{d}{d x} (21 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (20 x^{2}) = 40 x

\frac{d}{d x} (21 x) = 21

= - 3 x^{2} + 40 x + 21

y^{^{''}} + 4 y = x^{2}

y^{^{'}} = \frac{3 x}{y}

\frac{d}{d x} (\frac{ln ( 3 x ^{2} - 6 x )}{4 x ^{3} - 2})

\int (ln (x))^{7} d x

\frac{d}{d x} (4 sec (4 x))

What is the derivative of-x^3+20x^2+21x ?
The derivative of-x^3+20x^2+21x is -3x^2+40x+21
What is the first derivative of-x^3+20x^2+21x ?
The first derivative of-x^3+20x^2+21x is -3x^2+40x+21