What is the derivative of 4sec(4x) ?

The derivative of 4sec(4x) is 16sec(4x)tan(4x)

What is the first derivative of 4sec(4x) ?

The first derivative of 4sec(4x) is 16sec(4x)tan(4x)

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\frac{d}{d x} (4 sec (4 x))

16 sec (4 x) tan (4 x)

Solution steps

\frac{d}{d x} (4 sec (4 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (sec (4 x))

Apply the chain rule:

sec (4 x) tan (4 x) \frac{d}{d x} (4 x)

= sec (4 x) tan (4 x) \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= 4 sec (4 x) tan (4 x) \cdot 4

Simplify

= 16 sec (4 x) tan (4 x)

\int e^{(x + 1)} d x

n = 1 \sum \infty cos (\frac{1}{n})

x \frac{d y}{d x} + 6 y = x^{3} - x

y^{^{'}} - cos (t) y = t e^{t^{2} + s i n (t)}

\frac{d}{d x} (20 (1 - e^{- \frac{x}{2}}))

What is the derivative of 4sec(4x) ?
The derivative of 4sec(4x) is 16sec(4x)tan(4x)
What is the first derivative of 4sec(4x) ?
The first derivative of 4sec(4x) is 16sec(4x)tan(4x)