What is the derivative of 5(2-7x^4) ?

The derivative of 5(2-7x^4) is -140(2-7x)^3

What is the first derivative of 5(2-7x^4) ?

The first derivative of 5(2-7x^4) is -140(2-7x)^3

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\frac{d}{d x} (5 (2 - 7 x)^{4})

- 140 (2 - 7 x)^{3}

Solution steps

\frac{d}{d x} (5 (2 - 7 x)^{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} ((2 - 7 x)^{4})

Apply the chain rule:

4 (2 - 7 x)^{3} \frac{d}{d x} (2 - 7 x)

= 4 (2 - 7 x)^{3} \frac{d}{d x} (2 - 7 x)

\frac{d}{d x} (2 - 7 x) = - 7

= 5 \cdot 4 (2 - 7 x)^{3} (- 7)

Simplify

= - 140 (2 - 7 x)^{3}

x^{3} + \frac{1}{x ^{2}} + 3

x + \frac{1}{x}

\int 6 e^{- t} d t

\int_{0}^{\frac{π}{6}} 9 sec^{2} (x) d x

\int \frac{1}{( x ^{2} x ^{2} - 4 )} d x

What is the derivative of 5(2-7x^4) ?
The derivative of 5(2-7x^4) is -140(2-7x)^3
What is the first derivative of 5(2-7x^4) ?
The first derivative of 5(2-7x^4) is -140(2-7x)^3