What is the integral of (tan^2(x)+1) ?

The integral of (tan^2(x)+1) is tan(x)+C

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integral of (tan^2(x)+1)

\int (tan^{2} (x) + 1) d x

tan (x) + C

Solution steps

\int tan^{2} (x) + 1 d x

Rewrite using trig identities

= \int sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= tan (x)

Add a constant to the solution

= tan (x) + C

f (x) = 9 sin (3 x)

\frac{d}{d y} (x + y^{2})

\int x 2 - x^{2} - x^{2} d x

\frac{d y}{d x} = \frac{sec ( y )}{( x - 4 ) ^{2}}

\int 2 x e^{x^{2}} csc^{2} (e^{x^{2}}) d x