What is the first derivative of 2Ax ?

The first derivative of 2Ax is 2A

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derivative of 2Ax

\frac{d}{d x} (2 A x)

2 A

Solution steps

\frac{d}{d x} (2 A x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 A \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= 2 A \cdot 1

Simplify

= 2 A

y^{^{'}} = 2 y - 3 y^{2}

\frac{d y}{d x} = x + 8

\frac{1}{2 ( s + 1 )}

(2.8) (0.6)

f (x) = \frac{x}{8 x ^{3} - 2 x + 9}