What is the slope ofintercept (2.8)(0.6) ?

The slope ofintercept (2.8)(0.6) is y=2.8*0.6

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slope ofintercept (2.8)(0.6)

slope intercept

(2.8) (0.6)

y = 2.8 \cdot 0.6

Solution steps

y = 2.8 \cdot 0.6

The equation

y = b

is a horizontal line, therefore the slope is

0

and the intercept is

b

y = 2.8 \cdot 0.6

f (x) = \frac{x}{8 x ^{3} - 2 x + 9}

\frac{d}{d x} (\frac{arctan ( x )}{x})

cos (e^{x^{5} s i n (x)})

y^{^{''}} - 4 y^{^{'}} + 4 y = (18 x - 4) e^{2 x}

\frac{d y}{d t} - y cos (t) = cos (t)

What is the slope ofintercept (2.8)(0.6) ?
The slope ofintercept (2.8)(0.6) is y=2.8*0.6