What is the solution for (dy)/(dt)-ycos(t)=cos(t) ?

The solution for (dy)/(dt)-ycos(t)=cos(t) is y=e^{sin(t)+c_{1}}-1

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(dy)/(dt)-ycos(t)=cos(t)

\frac{d y}{d t} - y cos (t) = cos (t)

y = e^{s i n (t) + c_{1}} - 1

Solution steps

\frac{d y}{d t} - y cos (t) = cos (t)

Solve separable ODE:

y = e^{s i n (t) + c_{1}} - 1

y = e^{s i n (t) + c_{1}} - 1

\int_{0}^{l n (6)} e^{x} - e^{- 2 x} d x

\int x - 2 d x

\int 6 sin^{3} (x) cos^{2} (x) d x

\int x cos^{2} (x) sin (x) d x

f (x) = x^{2} - 1, (- 2, 3)

What is the solution for (dy)/(dt)-ycos(t)=cos(t) ?
The solution for (dy)/(dt)-ycos(t)=cos(t) is y=e^{sin(t)+c_{1}}-1