What is the derivative of 2w^{3pi},\at 7 ?

The derivative of 2w^{3pi},\at 7 is 6piw^{3pi-1}

What is the first derivative of 2w^{3pi},\at 7 ?

The first derivative of 2w^{3pi},\at 7 is 6piw^{3pi-1}

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derivative of

2 w^{3 π}, at 7

6 π w^{3 π - 1}

Solution steps

\frac{d}{d w} (2 w^{3 π})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d w} (w^{3 π})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 3 π w^{3 π - 1}

Simplify

= 6 π w^{3 π - 1}

\frac{k}{s}

6 sec (x) tan (x)

n = 3 \sum \infty \frac{6}{n ( n - 2 )}

\frac{x ^{2} - 7 x + 3}{x ^{2} + 7}

y^{^{''}} + 4 y^{^{'}} + 5 y = 15 x + 5 e^{- x}

What is the derivative of 2w^{3pi},\at 7 ?
The derivative of 2w^{3pi},\at 7 is 6piw^{3pi-1}
What is the first derivative of 2w^{3pi},\at 7 ?
The first derivative of 2w^{3pi},\at 7 is 6piw^{3pi-1}