What is the limit as x approaches 0 of (1+2x)^{1/(2x^2)} ?

The limit as x approaches 0 of (1+2x)^{1/(2x^2)} is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of (1+2x)^{1/(2x^2)}

x \to 0 lim ((1 + 2 x)^{\frac{1}{2 x ^{2}}})

diverges

Solution steps

x \to 0 lim ((1 + 2 x)^{\frac{1}{2 x ^{2}}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim ((1 + 2 x)^{\frac{1}{2 x ^{2}}}) = \infty

x \to 0 - lim ((1 + 2 x)^{\frac{1}{2 x ^{2}}}) = 0

= diverges

\frac{d}{d x} (2 sin^{3} (x))

\int_{- 2}^{3} x^{2} - 4 d x

\int \frac{- 3}{y} d y

18 e^{t}

f (x) = \frac{3}{x}, at x = 4

What is the limit as x approaches 0 of (1+2x)^{1/(2x^2)} ?
The limit as x approaches 0 of (1+2x)^{1/(2x^2)} is diverges