What is the derivative of x^3-6x^2+9x-4 ?

The derivative of x^3-6x^2+9x-4 is 3x^2-12x+9

What is the first derivative of x^3-6x^2+9x-4 ?

The first derivative of x^3-6x^2+9x-4 is 3x^2-12x+9

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\frac{d}{d x} (x^{3} - 6 x^{2} + 9 x - 4)

3 x^{2} - 12 x + 9

Solution steps

\frac{d}{d x} (x^{3} - 6 x^{2} + 9 x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (6 x^{2}) + \frac{d}{d x} (9 x) - \frac{d}{d x} (4)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (9 x) = 9

\frac{d}{d x} (4) = 0

= 3 x^{2} - 12 x + 9 - 0

Simplify

= 3 x^{2} - 12 x + 9

\int (x + 1) (x^{2} + 2 x) d x

\frac{d}{d x} (\frac{( x ^{4} )}{8} + \frac{1}{4 x ^{2}})

x \to - 3 lim (\frac{2}{x ^{2} - 9})

x y^{^{'}} = 2 x^{2} + y

\frac{d y}{d x} = 3 y^{2}

What is the derivative of x^3-6x^2+9x-4 ?
The derivative of x^3-6x^2+9x-4 is 3x^2-12x+9
What is the first derivative of x^3-6x^2+9x-4 ?
The first derivative of x^3-6x^2+9x-4 is 3x^2-12x+9