What is the solution for y^'=((6x^3+y^3))/(xy^2) ?

The solution for y^'=((6x^3+y^3))/(xy^2) is y=x\sqrt[3]{18ln(x)+c_{1}}

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y^'=((6x^3+y^3))/(xy^2)

y^{^{'}} = \frac{( 6 x ^{3} + y ^{3} )}{x y ^{2}}

Solution steps

y^{'} (x) = \frac{( 6 x ^{3} + y ^{3} )}{x y ^{2}}

Solve Bernoulli ODE:

y^{^{'}} = 1 - 100 (y - t)

\int_{0}^{\infty} \frac{1}{x ^{2}} d x

\int \frac{2 x + 1}{( x ^{2} + 6 x + 10 ) ( x + 1 )} d x

x \to - 6 lim (\frac{x ^{2} - 8}{6 - x})

\int_{- 2}^{2} (- x^{2} + 4)^{2} d x

What is the solution for y^'=((6x^3+y^3))/(xy^2) ?
The solution for y^'=((6x^3+y^3))/(xy^2) is y=x\sqrt[3]{18ln(x)+c_{1}}