What is the derivative of (2-x^2/((2+x^2)^2)) ?

The derivative of (2-x^2/((2+x^2)^2)) is -(2x(-x^2+6))/((x^2+2)^3)

What is the first derivative of (2-x^2/((2+x^2)^2)) ?

The first derivative of (2-x^2/((2+x^2)^2)) is -(2x(-x^2+6))/((x^2+2)^3)

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\frac{d}{d x} (\frac{2 - x ^{2}}{( 2 + x ^{2} ) ^{2}})

- \frac{2 x ( - x ^{2} + 6 )}{( x ^{2} + 2 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{2 - x ^{2}}{( 2 + x ^{2} ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 - x ^{2} ) ( 2 + x ^{2} ) ^{2} - \frac{d}{d x} ( ( 2 + x ^{2} ) ^{2} ) ( 2 - x ^{2} )}{( ( 2 + x ^{2} ) ^{2} ) ^{2}}

\frac{d}{d x} (2 - x^{2}) = - 2 x

\frac{d}{d x} ((2 + x^{2})^{2}) = 4 x (2 + x^{2})

= \frac{( - 2 x ) ( 2 + x ^{2} ) ^{2} - 4 x ( 2 + x ^{2} ) ( 2 - x ^{2} )}{( ( 2 + x ^{2} ) ^{2} ) ^{2}}

Simplify

\frac{( - 2 x ) ( 2 + x ^{2} ) ^{2} - 4 x ( 2 + x ^{2} ) ( 2 - x ^{2} )}{( ( 2 + x ^{2} ) ^{2} ) ^{2}} : - \frac{2 x ( - x ^{2} + 6 )}{( x ^{2} + 2 ) ^{3}}

= - \frac{2 x ( - x ^{2} + 6 )}{( x ^{2} + 2 ) ^{3}}

- x^{2} + 4 x, x^{2} - 2 x

f (x) = 8 e^{x} cos (x)

\frac{s}{( s ^{2} + 2 s + 2 ) ( s ^{2} + 4 )}

f (x) = - x^{2} - 4 x + 1, at x = - 4

f (x) = ln (8 x)

What is the derivative of (2-x^2/((2+x^2)^2)) ?
The derivative of (2-x^2/((2+x^2)^2)) is -(2x(-x^2+6))/((x^2+2)^3)
What is the first derivative of (2-x^2/((2+x^2)^2)) ?
The first derivative of (2-x^2/((2+x^2)^2)) is -(2x(-x^2+6))/((x^2+2)^3)