What is the derivative of f(x)=8e^xcos(x) ?

The derivative of f(x)=8e^xcos(x) is 8(e^xcos(x)-e^xsin(x))

What is the first derivative of f(x)=8e^xcos(x) ?

The first derivative of f(x)=8e^xcos(x) is 8(e^xcos(x)-e^xsin(x))

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derivative of

f (x) = 8 e^{x} cos (x)

8 (e^{x} cos (x) - e^{x} sin (x))

Solution steps

\frac{d}{d x} (8 e^{x} cos (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (e^{x} cos (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{x}, g = cos (x)

= 8 (\frac{d}{d x} (e^{x}) cos (x) + \frac{d}{d x} (cos (x)) e^{x})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (cos (x)) = - sin (x)

= 8 (e^{x} cos (x) + (- sin (x)) e^{x})

Simplify

= 8 (e^{x} cos (x) - e^{x} sin (x))

\frac{s}{( s ^{2} + 2 s + 2 ) ( s ^{2} + 4 )}

f (x) = - x^{2} - 4 x + 1, at x = - 4

f (x) = ln (8 x)

\int 8 (x + 1) d x

\int \frac{( x ^{5} - 2 x ^{2} )}{( 1 + x ^{3} ) ^{\frac{3}{2}}} d x

What is the derivative of f(x)=8e^xcos(x) ?
The derivative of f(x)=8e^xcos(x) is 8(e^xcos(x)-e^xsin(x))
What is the first derivative of f(x)=8e^xcos(x) ?
The first derivative of f(x)=8e^xcos(x) is 8(e^xcos(x)-e^xsin(x))