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Popular >

integral of 8(x+1)

Solution

\int 8 (x + 1) d x

Solution

8 (\frac{x ^{2}}{2} + x) + C

Solution steps

\int 8 (x + 1) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 8 (\int x d x + \int 1 d x)

\int x d x = \frac{x ^{2}}{2}

\int 1 d x = x

= 8 (\frac{x ^{2}}{2} + x)

Add a constant to the solution

= 8 (\frac{x ^{2}}{2} + x) + C

Popular Examples

integral of ((x^5-2x^2))/((1+x^3)^{3/2)}

\int \frac{( x ^{5} - 2 x ^{2} )}{( 1 + x ^{3} ) ^{\frac{3}{2}}} d x

integral of \sqrt[6]{e^x}

derivative of f(x)= 1/(x+1)derivative of

f (x) = \frac{1}{x + 1}

tangent of f(x)=x^2+4,(-4,20)tangent of

f (x) = x^{2} + 4, (- 4, 20)

\frac{d}{d u} (2 uv)

Frequently Asked Questions (FAQ)

What is the integral of 8(x+1) ?
The integral of 8(x+1) is 8((x^2)/2+x)+C