What is the derivative of (x^2-9/(x-3)) ?

The derivative of (x^2-9/(x-3)) is 1

What is the first derivative of (x^2-9/(x-3)) ?

The first derivative of (x^2-9/(x-3)) is 1

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\frac{d}{d x} (\frac{x ^{2} - 9}{x - 3})

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 9}{x - 3})

Simplify

\frac{x ^{2} - 9}{x - 3} : x + 3

= \frac{d}{d x} (x + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (3)

\frac{d x}{d x} = 1

\frac{d}{d x} (3) = 0

= 1 + 0

Simplify

= 1

\frac{\partial}{\partial u ( v )} (\frac{e ^{v}}{u ( v ) + v ^{3}})

\int_{1}^{\infty} \frac{5}{x ^{2} + 1} d x

n = 2 \sum \infty \frac{( - 1 ) ^{n}}{n}

\int x^{3} e^{- 2 x} d x

\frac{d}{d j} (12 i + 15 j)

What is the derivative of (x^2-9/(x-3)) ?
The derivative of (x^2-9/(x-3)) is 1
What is the first derivative of (x^2-9/(x-3)) ?
The first derivative of (x^2-9/(x-3)) is 1