What is the derivative of (x^2/8-1/x) ?

The derivative of (x^2/8-1/x) is x/4+1/(x^2)

What is the first derivative of (x^2/8-1/x) ?

The first derivative of (x^2/8-1/x) is x/4+1/(x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{x ^{2}}{8} - \frac{1}{x})

\frac{x}{4} + \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{8} - \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{2}}{8}) - \frac{d}{d x} (\frac{1}{x})

\frac{d}{d x} (\frac{x ^{2}}{8}) = \frac{x}{4}

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= \frac{x}{4} - (- \frac{1}{x ^{2}})

Simplify

= \frac{x}{4} + \frac{1}{x ^{2}}

n = 5 \sum \infty n

\int \frac{x ^{2} + 3 x + 1}{x} d x

\int \frac{1}{3 x ^{2} + 4} d x

f (x) = - 2 x^{4} + 10 x^{2}, at x = - 1

\frac{d}{d x} (1 - \frac{2}{x ^{2}})

What is the derivative of (x^2/8-1/x) ?
The derivative of (x^2/8-1/x) is x/4+1/(x^2)
What is the first derivative of (x^2/8-1/x) ?
The first derivative of (x^2/8-1/x) is x/4+1/(x^2)