What is the solution for (t^2+1)(dy)/(dt)=yt-y ?

The solution for (t^2+1)(dy)/(dt)=yt-y is y=e^{-arctan(t)+c_{1}}sqrt(t^2+1)

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(t^2+1)(dy)/(dt)=yt-y

(t^{2} + 1) \frac{d y}{d t} = y t - y

y = e^{- a r c t a n (t) + c_{1}} t^{2} + 1

Solution steps

(t^{2} + 1) \frac{d y}{d t} = y t - y

Solve separable ODE:

y = e^{- a r c t a n (t) + c_{1}} t^{2} + 1

y = e^{- a r c t a n (t) + c_{1}} t^{2} + 1

n = 1 \sum \infty \frac{1}{n 8 ^{n}}

\int \frac{1}{3 + 25 x ^{2}} d x

\int cot^{6} (x) d x

(- 7.6) (4.2)

What is the solution for (t^2+1)(dy)/(dt)=yt-y ?
The solution for (t^2+1)(dy)/(dt)=yt-y is y=e^{-arctan(t)+c_{1}}sqrt(t^2+1)