What is the solution for (d^2y)/(dt^2)+4(dy)/(dt)+4y=0 ?

The solution for (d^2y)/(dt^2)+4(dy)/(dt)+4y=0 is y=c_{1}e^{-2t}+c_{2}te^{-2t}

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(d^2y)/(dt^2)+4(dy)/(dt)+4y=0

\frac{d ^{2} y}{d t ^{2}} + 4 \frac{d y}{d t} + 4 y = 0

y = c_{1} e^{- 2 t} + c_{2} t e^{- 2 t}

Solution steps

\frac{d ^{2} y}{d t ^{2}} + 4 \frac{d y}{d t} + 4 y = 0

Solve linear ODE:

y = c_{1} e^{- 2 t} + c_{2} t e^{- 2 t}

y = c_{1} e^{- 2 t} + c_{2} t e^{- 2 t}

\int \frac{1}{e ^{x} + 1} d x

\frac{\partial}{\partial t} (s \cdot cos (t))

\frac{d}{d y} (1 + y^{2})

f (x) = 2 x^{2} + 4, at x = - 2

z \to 1 + i lim (z^{2} - 5 z + 10)

What is the solution for (d^2y)/(dt^2)+4(dy)/(dt)+4y=0 ?
The solution for (d^2y)/(dt^2)+4(dy)/(dt)+4y=0 is y=c_{1}e^{-2t}+c_{2}te^{-2t}