What is the tangent of f(x)=2x^2+4,\at x=-2 ?

The tangent of f(x)=2x^2+4,\at x=-2 is y=-8x-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=2x^2+4,\at x=-2

tangent of

f (x) = 2 x^{2} + 4, at x = - 2

y = - 8 x - 4

Solution steps

Find the tangent point:

(- 2, 12)

Find the slope of

f (x) = 2 x^{2} + 4 : \frac{df ( x )}{d x} = 4 x

Compute the slope of

f (x) = 2 x^{2} + 4

x = - 2 : m = - 8

Find the line with slope m=

- 8

and passing through

(- 2, 12) : y = - 8 x - 4

y = - 8 x - 4

z \to 1 + i lim (z^{2} - 5 z + 10)

y^{^{'}} = 2 y - 4 x

x \to - 3 lim (\frac{x}{x + 3})

x \to 0 lim (\frac{x - x cos ( x )}{sin ^{2} ( 3 x )})

\frac{d}{d x} (2 x^{3} - 3 x^{2} - 36 x)

What is the tangent of f(x)=2x^2+4,\at x=-2 ?
The tangent of f(x)=2x^2+4,\at x=-2 is y=-8x-4