What is the derivative of 2x^3-3x^2-36x ?

The derivative of 2x^3-3x^2-36x is 6x^2-6x-36

What is the first derivative of 2x^3-3x^2-36x ?

The first derivative of 2x^3-3x^2-36x is 6x^2-6x-36

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\frac{d}{d x} (2 x^{3} - 3 x^{2} - 36 x)

6 x^{2} - 6 x - 36

Solution steps

\frac{d}{d x} (2 x^{3} - 3 x^{2} - 36 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (36 x)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (36 x) = 36

= 6 x^{2} - 6 x - 36

x \to - \infty lim (\frac{2}{x} - 3)

n \to \infty lim (\frac{1}{2})

\int x^{3} \cdot e^{- x} d x

f (x) = \frac{5}{x}, (- 3, (- \frac{5}{3}))

\frac{d x}{d t} + 3 = 0

What is the derivative of 2x^3-3x^2-36x ?
The derivative of 2x^3-3x^2-36x is 6x^2-6x-36
What is the first derivative of 2x^3-3x^2-36x ?
The first derivative of 2x^3-3x^2-36x is 6x^2-6x-36