What is the integral of cos^2(2t) ?

The integral of cos^2(2t) is 1/2 (t+1/4 sin(4t))+C

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integral of cos^2(2t)

\int cos^{2} (2 t) d t

\frac{1}{2} (t + \frac{1}{4} sin (4 t)) + C

Solution steps

\int cos^{2} (2 t) d t

Rewrite using trig identities

= \int \frac{1}{2} (1 + cos (4 t)) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int 1 + cos (4 t) d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int 1 d t + \int cos (4 t) d t)

\int 1 d t = t

\int cos (4 t) d t = \frac{1}{4} sin (4 t)

= \frac{1}{2} (t + \frac{1}{4} sin (4 t))

Add a constant to the solution

= \frac{1}{2} (t + \frac{1}{4} sin (4 t)) + C

y^{^{''}} + 9 = 0

- 2 π sin (4 π x)

\frac{d}{d x} (230 - 8 x + 0.04 x^{2})

\frac{d}{d x} (\frac{csc ( x ) \cdot tan ( x )}{cos ( x )})

\frac{\partial}{\partial x} ((1 - x^{2} - y^{2})^{\frac{1}{2}})

What is the integral of cos^2(2t) ?
The integral of cos^2(2t) is 1/2 (t+1/4 sin(4t))+C