What is the derivative of 4x^2-5x ?

The derivative of 4x^2-5x is 8x-5

What is the first derivative of 4x^2-5x ?

The first derivative of 4x^2-5x is 8x-5

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derivative of

4 x^{2} - 5 x

8 x - 5

Solution steps

\frac{d}{d x} (4 x^{2} - 5 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) - \frac{d}{d x} (5 x)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (5 x) = 5

= 8 x - 5

\frac{\partial}{\partial x} (sin (x \cdot e^{x^{2} \cdot y}))

\int (sin^{3} (2 t)) cos (2 t) d t

x \to 9 + lim (ln (x^{2} - 81))

\int e^{x} 6 - e^{x} d x

(3 x^{2})^{^{'}}

What is the derivative of 4x^2-5x ?
The derivative of 4x^2-5x is 8x-5
What is the first derivative of 4x^2-5x ?
The first derivative of 4x^2-5x is 8x-5