What is the limit as x approaches 4 of x^2-4x+1 ?

The limit as x approaches 4 of x^2-4x+1 is 1

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limit as x approaches 4 of x^2-4x+1

x \to 4 lim (x^{2} - 4 x + 1)

1

Solution steps

x \to 4 lim (x^{2} - 4 x + 1)

Plug in the value

x = 4

= 4^{2} - 4 \cdot 4 + 1

Simplify

= 1

f (x) = 3 x - 5

\int \frac{16 x ^{2}}{( x - 9 ) ( x + 3 ) ^{2}} d x

\frac{d}{d x} ((5 x - 4) (2 x^{3} - x^{2} + 1))

f (x) = \frac{1}{4 + 3 x}, (1, \frac{1}{7})

e^{9 x}

What is the limit as x approaches 4 of x^2-4x+1 ?
The limit as x approaches 4 of x^2-4x+1 is 1