What is the tangent of f(x)= 1/(4+3x),(1, 1/7) ?

The tangent of f(x)= 1/(4+3x),(1, 1/7) is y=-3/49 x+10/49

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tangent of f(x)= 1/(4+3x),(1, 1/7)

tangent of

f (x) = \frac{1}{4 + 3 x}, (1, \frac{1}{7})

y = - \frac{3}{49} x + \frac{10}{49}

Solution steps

Find the slope of

f (x) = \frac{1}{4 + 3 x} : \frac{df ( x )}{d x} = - \frac{3}{( 4 + 3 x ) ^{2}}

Compute the slope of

f (x) = \frac{1}{4 + 3 x}

(1, \frac{1}{7}) : m = - \frac{3}{49}

Find the line with slope m=

- \frac{3}{49}

and passing through

(1, \frac{1}{7}) : y = - \frac{3}{49} x + \frac{10}{49}

y = - \frac{3}{49} x + \frac{10}{49}

e^{9 x}

f (x) = 2 x^{2} - 4 x + 1

\int \frac{1}{x ^{\frac{5}{8}} - x ^{\frac{1}{8}}} d x

\int 31 arctan (x) d x

\int_{1}^{4} 3 x^{\frac{1}{3}} d x

What is the tangent of f(x)= 1/(4+3x),(1, 1/7) ?
The tangent of f(x)= 1/(4+3x),(1, 1/7) is y=-3/49 x+10/49