What is the derivative of f(x)=2x^2-4x+1 ?

The derivative of f(x)=2x^2-4x+1 is 4x-4

What is the first derivative of f(x)=2x^2-4x+1 ?

The first derivative of f(x)=2x^2-4x+1 is 4x-4

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derivative of

f (x) = 2 x^{2} - 4 x + 1

4 x - 4

Solution steps

\frac{d}{d x} (2 x^{2} - 4 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (1) = 0

= 4 x - 4 + 0

Simplify

= 4 x - 4

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\frac{d}{d x} (lo g_{2} (7 x^{2} + x - 2))

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What is the derivative of f(x)=2x^2-4x+1 ?
The derivative of f(x)=2x^2-4x+1 is 4x-4
What is the first derivative of f(x)=2x^2-4x+1 ?
The first derivative of f(x)=2x^2-4x+1 is 4x-4