What is the integral from 1 to 4 of 3x^{1/3} ?

The integral from 1 to 4 of 3x^{1/3} is 3(3*4^{1/3}-3/4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 4 of 3x^{1/3}

\int_{1}^{4} 3 x^{\frac{1}{3}} d x

3 (3 \cdot 4^{\frac{1}{3}} - \frac{3}{4})

Decimal Notation

12.03660 \dots

Solution steps

\int_{1}^{4} 3 x^{\frac{1}{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{1}^{4} x^{\frac{1}{3}} d x

Apply the Power Rule

: [\frac{3}{4} x^{\frac{4}{3}}]_{1}^{4}

= 3 [\frac{3}{4} x^{\frac{4}{3}}]_{1}^{4}

Compute the boundaries:

3 \cdot 4^{\frac{1}{3}} - \frac{3}{4}

= 3 (3 \cdot 4^{\frac{1}{3}} - \frac{3}{4})

\frac{d}{d x} (lo g_{2} (7 x^{2} + x - 2))

\frac{d}{d x} (12 x - x^{2})

x \to 1 lim (\frac{( x + 1 )}{x - 1})

\frac{d}{d x} (x^{2} - \frac{1}{8} ln (x))

\int e^{- 2 t} t d t

What is the integral from 1 to 4 of 3x^{1/3} ?
The integral from 1 to 4 of 3x^{1/3} is 3(3*4^{1/3}-3/4)