What is the derivative of x^2-1/8 ln(x) ?

The derivative of x^2-1/8 ln(x) is 2x-1/(8x)

What is the first derivative of x^2-1/8 ln(x) ?

The first derivative of x^2-1/8 ln(x) is 2x-1/(8x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x^{2} - \frac{1}{8} ln (x))

2 x - \frac{1}{8 x}

Solution steps

\frac{d}{d x} (x^{2} - \frac{1}{8} ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (\frac{1}{8} ln (x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (\frac{1}{8} ln (x)) = \frac{1}{8 x}

= 2 x - \frac{1}{8 x}

\int e^{- 2 t} t d t

y^{^{''}} + 6 y^{^{'}} + 9 y = \frac{( e ^{- 3 x} )}{x}

\int \frac{( x ^{2} )}{x ^{2} + 64} d x

\frac{d}{d x} (\frac{- x + 6}{2 ( 2 - x ) 2 - x})

n = 0 \sum \infty \frac{4}{2 n + 1}

What is the derivative of x^2-1/8 ln(x) ?
The derivative of x^2-1/8 ln(x) is 2x-1/(8x)
What is the first derivative of x^2-1/8 ln(x) ?
The first derivative of x^2-1/8 ln(x) is 2x-1/(8x)