What is the derivative of x^2+5x+9 ?

The derivative of x^2+5x+9 is 2x+5

What is the first derivative of x^2+5x+9 ?

The first derivative of x^2+5x+9 is 2x+5

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derivative of

x^{2} + 5 x + 9

2 x + 5

Solution steps

\frac{d}{d x} (x^{2} + 5 x + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (5 x) + \frac{d}{d x} (9)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (9) = 0

= 2 x + 5 + 0

Simplify

= 2 x + 5

x \to 5 lim (x - 1)

f (x) = cos (x) - x sin (x)

\frac{d v}{d t} = 4.9 - (\frac{100 v}{2.5})

y = 3 49 - x^{2}, y = 0, x = 2, x = 4

\frac{\partial}{\partial x} (2 x cos (4 x y))

What is the derivative of x^2+5x+9 ?
The derivative of x^2+5x+9 is 2x+5
What is the first derivative of x^2+5x+9 ?
The first derivative of x^2+5x+9 is 2x+5