What is the solution for (dv)/(dt)=4.9-((100v)/(2.5)) ?

The solution for (dv)/(dt)=4.9-((100v)/(2.5)) is v=-0.01e^{-40t-c_{1}}+0.1225

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dv)/(dt)=4.9-((100v)/(2.5))

\frac{d v}{d t} = 4.9 - (\frac{100 v}{2.5})

v = - 0.01 e^{- 40 t - c_{1}} + 0.1225

Solution steps

\frac{d v}{d t} = 4.9 - (\frac{100 v}{2.5})

Solve separable ODE:

v = - 0.01 e^{- 40 t - c_{1}} + 0.1225

v = - 0.01 e^{- 40 t - c_{1}} + 0.1225

y = 3 49 - x^{2}, y = 0, x = 2, x = 4

\frac{\partial}{\partial x} (2 x cos (4 x y))

f (t) = 3 δ (t) + 2 + 4 e^{- 3 t + 2}

y^{^{'}} (x) = \frac{9 x ^{2}}{9 y ^{2} - 11}, y (11) = 0

f (x) = 675 - 4.9 x^{2}

What is the solution for (dv)/(dt)=4.9-((100v)/(2.5)) ?
The solution for (dv)/(dt)=4.9-((100v)/(2.5)) is v=-0.01e^{-40t-c_{1}}+0.1225