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Popular >

integral of 2t-5

Solution

\int 2 t - 5 d t

Solution

t^{2} - 5 t + C

Solution steps

\int 2 t - 5 d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 t d t - \int 5 d t

\int 2 t d t = t^{2}

\int 5 d t = 5 t

= t^{2} - 5 t

Add a constant to the solution

= t^{2} - 5 t + C

Popular Examples

(dy)/(dx)=sqrt(x/y)

\frac{d y}{d x} = \frac{x}{y}

(dy)/(dx)=((2sec(y)))/((x-4)^2)

\frac{d y}{d x} = \frac{( 2 sec ( y ) )}{( x - 4 ) ^{2}}

sum from n=2 to infinity of 1/(2^n)

n = 2 \sum \infty \frac{1}{2 ^{n}}

derivative of 2x^2+4y^2 derivative of

2 x^{2} + 4 y^{2}

limit as x approaches 1+of ln(x^{x-1})

x \to 1 + lim (ln (x^{x - 1}))

Frequently Asked Questions (FAQ)

What is the integral of 2t-5 ?
The integral of 2t-5 is t^2-5t+C