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Popular >

limit as x approaches 1+of ln(x^{x-1})

Solution

x \to 1 + lim (ln (x^{x - 1}))

Solution

0

Solution steps

x \to 1 + lim (ln (x^{x - 1}))

Plug in the value

x = 1

= ln (1^{1 - 1})

Simplify

ln (1^{1 - 1}) : 0

= 0

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Frequently Asked Questions (FAQ)

What is the limit as x approaches 1+of ln(x^{x-1}) ?
The limit as x approaches 1+of ln(x^{x-1}) is 0