What is the derivative of (1+x^2^3) ?

The derivative of (1+x^2^3) is 6x(1+x^2)^2

What is the first derivative of (1+x^2^3) ?

The first derivative of (1+x^2^3) is 6x(1+x^2)^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} ((1 + x^{2})^{3})

6 x (1 + x^{2})^{2}

Solution steps

\frac{d}{d x} ((1 + x^{2})^{3})

Apply the chain rule:

3 (1 + x^{2})^{2} \frac{d}{d x} (1 + x^{2})

= 3 (1 + x^{2})^{2} \frac{d}{d x} (1 + x^{2})

\frac{d}{d x} (1 + x^{2}) = 2 x

= 3 (1 + x^{2})^{2} \cdot 2 x

Simplify

= 6 x (1 + x^{2})^{2}

\frac{d}{d x} (108 x)

x \to 1 lim (\frac{x}{x + 1})

f (x) = 0.8 e^{x} arctan (x)

\int 15.7 - 0.2 x d x

\int_{- \infty}^{0} x e^{- 4 x} d x

What is the derivative of (1+x^2^3) ?
The derivative of (1+x^2^3) is 6x(1+x^2)^2
What is the first derivative of (1+x^2^3) ?
The first derivative of (1+x^2^3) is 6x(1+x^2)^2