What is the integral from-infinity to 0 of xe^{-4x} ?

The integral from-infinity to 0 of xe^{-4x} is diverges

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integral from-infinity to 0 of xe^{-4x}

\int_{- \infty}^{0} x e^{- 4 x} d x

diverges

Solution steps

\int_{- \infty}^{0} x e^{- 4 x} d x

Compute the indefinite integral:

\int x e^{- 4 x} d x = \frac{1}{16} (- 4 e^{- 4 x} x - e^{- 4 x}) + C

Compute the boundaries:

\int_{- \infty}^{0} x e^{- 4 x} d x =

diverges

= diverges

n = 1 \sum \infty \frac{1}{n ^{1}}

\int_{4}^{9} 3 x d x

\int 3 x^{3} cos (x) d x

f (x) = x^{2} - 5 x + 5, at x = 0

\int x^{2} + 4 x d x

What is the integral from-infinity to 0 of xe^{-4x} ?
The integral from-infinity to 0 of xe^{-4x} is diverges