What is the tangent of f(x)=(sqrt(5))^x,\at x=4 ?

The tangent of f(x)=(sqrt(5))^x,\at x=4 is y=(25ln(5))/2 x+25-50ln(5)

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tangent of f(x)=(sqrt(5))^x,\at x=4

tangent of

f (x) = (5)^{x}, at x = 4

y = \frac{25 ln ( 5 )}{2} x + 25 - 50 ln (5)

Solution steps

Find the tangent point:

(4, 25)

Find the slope of

f (x) = (5)^{x} : \frac{df ( x )}{d x} = \frac{1}{2} ln (5) e^{\frac{l n ( 5 ) x}{2}}

Compute the slope of

f (x) = (5)^{x}

x = 4 : m = \frac{25 ln ( 5 )}{2}

Find the line with slope m=

\frac{25 ln ( 5 )}{2}

and passing through

(4, 25) : y = \frac{25 ln ( 5 )}{2} x + 25 - 50 ln (5)

y = \frac{25 ln ( 5 )}{2} x + 25 - 50 ln (5)

\int x^{2} 1 - x^{3} d x

\frac{d}{d θ} (8 sin (θ))

\int 17 x^{3} e^{x} d x

\frac{\partial}{\partial x} (\frac{4 y}{x ^{5}})

\frac{d}{d x} (ln (16 - 4 x^{2} - 4 y^{2} - z^{2}))

What is the tangent of f(x)=(sqrt(5))^x,\at x=4 ?
The tangent of f(x)=(sqrt(5))^x,\at x=4 is y=(25ln(5))/2 x+25-50ln(5)