What is the integral from 0 to 1 of x^{-2/3} ?

The integral from 0 to 1 of x^{-2/3} is 3

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integral from 0 to 1 of x^{-2/3}

\int_{0}^{1} x^{- \frac{2}{3}} d x

3

Solution steps

\int_{0}^{1} x^{- \frac{2}{3}} d x

Apply the Power Rule

: [3 x^{\frac{1}{3}}]_{0}^{1}

= [3 x^{\frac{1}{3}}]_{0}^{1}

Compute the boundaries:

3

= 3

\int \frac{x ^{2} - 3 x + 5}{x} d x

\frac{\partial}{\partial x} ((x - 3)^{2} + (y - 4)^{2})

\frac{d}{d y} (x e^{\frac{y}{z}})

\int \frac{( arctan ( x ) ) ^{3}}{x ^{2} + 1} d x

\frac{d}{d x} (2 sin (2 cos (x)))

What is the integral from 0 to 1 of x^{-2/3} ?
The integral from 0 to 1 of x^{-2/3} is 3